##### Number System-CAT
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# Consider four-digit numbers for which the first two digits are equal and the last two digits are also equal. How many are such numbers perfect squares? (2007)

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#### Now, If we divide any of the above numerals by 11.

(Note – all the numerals above (1122, 2233…8899), it can be seen, are divisible by 11 only)

We get $\frac { 1122 }{ 11 } =102$ (this form) where A=1 and B=2.

#### ▪ 11 x 16= 176, 11 x 49 = 539

Since only one product takes A0B form when A = 7 and B = 4, the numeral is 7744, there is only one square in AoB form. The answer is only 1 square.

Hence, the option (d) is correct.

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